DEDECMS相关文章以关键字怎么修改-DEDECMS

DEDECMS相干文章以要害字怎样修正？

DEDE的相干文章齐全没有相干，有冤家正在DEDE民间放出依据TAG显示相干文章，也是很没有错，惋惜我正在依据何处文章改DEDE代码后总是没有行，多是才能无限，当然也有多是代码有成绩

保举学习：织梦cms

如今终于出理解决方法：

1 正在 inc_functions.php 最初?>前 加之

代码以下:

//查问指定栏目里蕴含相应要害字的文章，并列出 
//参数阐明：$showImg 能否显示缩略图，0示意没有显示，1示意显示 
// $titleLen 题目长度，0示意有限 
// $rowCount 输入行数，0示意有限 
// $typeid 栏目ID，0示意一切栏目 
// $keyWord 要害字，字符串 
function ShowKeyWordArc($showImg,$titleLen,$rowCount,$typeid,$keyWord){ 
$dsql = new DedeSql(false); 
$sql = TypeGetSunID($typeid,$dsql); </p> <p>//要害字分词技巧 
$ks = explode(" ",$keyWord); 
foreach($ks as $k){ 
$k = trim($k); 
if ($k!="") { 
$kwsqlarr[] = " (xkzzz_archives.title like '%$k%')"; 
//$kwsqlarr[] = " (xkzzz_archives.keywords like '%$k%') "; //假如需求相干到其它文章的要害字，解除了此行正文 
} 
} 
$where = implode(' OR ',$kwsqlarr); </p> <p>$sql="Select tp.namerule,tp.typedir,xkzzz_full_search.aid,xkzzz_full_search.url,xkzzz_archives.* From xkzzz_full_search left join xkzzz_archives on xkzzz_full_search.aid=xkzzz_archives.ID left join xkzzz_arctype tp on xkzzz_archives.typeid=tp.ID where {$sql} and ((xkzzz_archives.title like '%".$keyWord."%') or $where) order by xkzzz_full_search.aid desc"; 
$dsql->SetQuery($sql); 
$dsql->Execute(); 
$ss=""; 
$i=0; 
while($row=$dsql->GetObject()){ 
$url=GetFileUrl($row->ID,$row->typeid,$row->senddate,$row->title,$row->ismake,$row->arcrank,$row->namerule,$row->typedir,$row->money); 
if ($showImg==0){ 
$ss=$ss."<LI><a href='".$url."' target=_blank>"; 
if ($titleLen!=0) $ss=$ss.cn_substr($row->title,$titleLen); 
else $ss=$ss.$row->title; 
$ss=$ss."</A></LI>"; 
}else{ 
$ss=$ss."<LI><span class='sjdqimggl'><a href='".$url."' target=_blank>"; </p> <p>if ($row->litpic!="") $ss=$ss."<img src='".$row->litpic."' alt='".$row->title."' />"; 
else $ss=$ss."<img src='/images/titl.gif'/>"; 
$ss=$ss."</a></span><span class='sjdqtxttl'><a href='".$url."' target=_blank>"; 
if ($titleLen!=0) $ss=$ss.cn_substr($row->title,$titleLen); 
else $ss=$ss.$row->title; 
$ss=$ss."</A></span></LI>"; 
} 
$i++; 
if (($rowCount!=0)&&($i>=$rowCount)) return $ss; 
} 
return $ss; 
}