PHP如何去掉指定字符?-PHP问题

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PHP若何去掉指定字符?

正在PHP中能够应用“str_replace()”函数去掉指定字符,该函数会将子字符串进行交换,其语法是“str_replace(sea,rep,sub) ”,应用时只要挪用该函数将指定字符交换为空便可。

代码示例

根本典范榜样

<?php
// 赋值: <body text='black'>
$bodytag = str_replace("%body%", "black", "<body text='%body%'>");
// 赋值: Hll Wrld f PHP
$vowels = array("a", "e", "i", "o", "u", "A", "E", "I", "O", "U");
$onlyconsonants = str_replace($vowels, "", "Hello World of PHP");
// 赋值: You should eat pizza, beer, and ice cream every day
$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array("fruits", "vegetables", "fiber");
$yu妹妹y   = array("pizza", "beer", "ice cream");
$newphrase = str_replace($healthy, $yu妹妹y, $phrase);
// 赋值: 2
$str = str_replace("ll", "", "good golly miss molly!", $count);
echo $count;
?>

交换典范榜样

<?php
// 交换程序
$str     = "Line 1\nLine 2\rLine 3\r\nLine 4\n";
$order   = array("\r\n", "\n", "\r");
$replace = '<br />';
// 起首交换 \r\n 字符,因而它们没有会被两次转换
$newstr = str_replace($order, $replace, $str);
// 输入 F ,由于 A 被 B 交换,B 又被 C 交换,以此类推...
// 因为从左到右顺次交换,终极 E 被 F 交换
$search  = array('A', 'B', 'C', 'D', 'E');
$replace = array('B', 'C', 'D', 'E', 'F');
$subject = 'A';
echo str_replace($search, $replace, $subject);
// 输入: apearpearle pear
// 因为下面提到的缘由
$letters = array('a', 'p');
$fruit   = array('apple', 'pear');
$text    = 'a p';
$output  = str_replace($letters, $fruit, $text);
echo $output;
?>

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